JSP和Servlet相互跳转

在之前写项目的时候遇到了JSP跳转Servlet的问题，一开始网上查教程的时候Servlet里也有HTML内容，以为可以直接跳，结果失败了，后续发现是需要讲Servlet对应的JAVA文件写入到web.xml之中去。

具体情况

当时是已经写好Servlet文件并且写好跳转到JSP，因为需要在到达之前将后端的数据传输给JSP将其打印为表格的形式。

@WebServlet(name = "ResultServlet", value = "/res")

public class ResultServlet extends HttpServlet {

@Override

protected void doGet(HttpServletRequest req, HttpServletResponse resp)throws ServletException, IOException {

String event=req.getParameter("event");

req.setAttribute("event",event);

String eventsCommand[]={"result women 1m springboard detail" ,

"result women 3m springboard detail" ,

"result women 10m platform detail" ,

"result women 3m synchronised detail" ,

"result women 10m synchronised detail" ,

"result men 1m springboard detail" ,

"result men 3m springboard detail" ,

"result men 10m platform detail" ,

"result men 3m synchronised detail" ,

"result men 10m synchronised detail"};

String events[]={

"women 1m springboard" ,

"women 3m springboard" ,

"women 10m platform" ,

"women 3m synchronised" ,

"women 10m synchronised" ,

"men 1m springboard" ,

"men 3m springboard" ,

"men 10m platform" ,

"men 3m synchronised" ,

"men 10m synchronised"

};

DataSourceImpl data = new DataSourceImpl();

for (int i = 0; i < eventsCommand.length; i++) {

List list=data.getEventDetail(eventsCommand[i]);

req.setAttribute(events[i],list);

}

req.getRequestDispatcher("result.jsp").forward(req,resp);

}

@Override

protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {

doGet(req,resp);

}

}

操作步骤

在tomcat里的WEB-INF文件夹，打开web.xml，往其中写入Servlet对应的映射和路径。

"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"

"http://java.sun.com/dtd/web-app_2_3.dtd" >

Archetype Created Web Application

Athlete

web.AthleteServlet

Result

web.ResultServlet

Schedule

web.ScheduleServlet

Athlete

/Athlete

Result

/Result

Schedule

/Schedule

index.jsp

index.html

之后跳转时需要用form来传输参数给Servlet

这样子就能实现jsp和servlet之间相互跳转了，记得路径要写对。 参考文献